本節(jié)向您介紹使用遺傳算法實現解決方案。
生成位模式
以下示例顯示了如何根據 One Max 問題生成一個包含15個字符串的位串。
如下所示導入必要的軟件包 -
import random
from deap import base, creator, tools
定義評估函數。 這是創(chuàng)建遺傳算法的第一步。
def eval_func(individual):
target_sum = 15
return len(individual) - abs(sum(individual) - target_sum)
現在,使用正確的參數創(chuàng)建工具箱 -
def create_toolbox(num_bits):
creator.create("FitnessMax", base.Fitness, weights=(1.0,))
creator.create("Individual", list, fitness=creator.FitnessMax)
初始化工具箱
toolbox = base.Toolbox()
toolbox.register("attr_bool", random.randint, 0, 1)
toolbox.register("individual", tools.initRepeat, creator.Individual,
toolbox.attr_bool, num_bits)
toolbox.register("population", tools.initRepeat, list, toolbox.individual)
注冊計算操作符 -
toolbox.register("evaluate", eval_func)
現在,注冊交叉運算符 -
toolbox.register("mate", tools.cxTwoPoint)
注冊一個可變運算符 -
toolbox.register("mutate", tools.mutFlipBit, indpb = 0.05)
定義育種操作符 -
toolbox.register("select", tools.selTournament, tournsize = 3)
return toolbox
if __name__ == "__main__":
num_bits = 45
toolbox = create_toolbox(num_bits)
random.seed(7)
population = toolbox.population(n = 500)
probab_crossing, probab_mutating = 0.5, 0.2
num_generations = 10
print('\nEvolution process starts')
評估整個人口 -
fitnesses = list(map(toolbox.evaluate, population))
for ind, fit in zip(population, fitnesses):
ind.fitness.values = fit
print('\nEvaluated', len(population), 'individuals')
經過幾代人的創(chuàng)建和迭代 -
for g in range(num_generations):
print("\n- Generation", g)
選擇下一代個人 -
offspring = toolbox.select(population, len(population))
現在,克隆選定的個人 -
offspring = list(map(toolbox.clone, offspring))
對后代應用交叉和變異 -
for child1, child2 in zip(offspring[::2], offspring[1::2]):
if random.random() < probab_crossing:
toolbox.mate(child1, child2)
刪除孩子的適應值
del child1.fitness.values
del child2.fitness.values
現在,應用突變 -
for mutant in offspring:
if random.random() < probab_mutating:
toolbox.mutate(mutant)
del mutant.fitness.values
評估與無效的健身個體 -
invalid_ind = [ind for ind in offspring if not ind.fitness.valid]
fitnesses = map(toolbox.evaluate, invalid_ind)
for ind, fit in zip(invalid_ind, fitnesses):
ind.fitness.values = fit
print('Evaluated', len(invalid_ind), 'individuals')
現在,用下一代個體替代人口 -
population[:] = offspring
打印當代人的統(tǒng)計數據 -
fits = [ind.fitness.values[0] for ind in population]
length = len(population)
mean = sum(fits) / length
sum2 = sum(x*x for x in fits)
std = abs(sum2 / length - mean**2)**0.5
print('Min =', min(fits), ', Max =', max(fits))
print('Average =', round(mean, 2), ', Standard deviation =',
round(std, 2))
print("\n- Evolution ends")
打印最終輸出 -
best_ind = tools.selBest(population, 1)[0]
print('\nBest individual:\n', best_ind)
print('\nNumber of ones:', sum(best_ind))
Following would be the output:
Evolution process starts
Evaluated 500 individuals
- Generation 0
Evaluated 295 individuals
Min = 32.0 , Max = 45.0
Average = 40.29 , Standard deviation = 2.61
- Generation 1
Evaluated 292 individuals
Min = 34.0 , Max = 45.0
Average = 42.35 , Standard deviation = 1.91
- Generation 2
Evaluated 277 individuals
Min = 37.0 , Max = 45.0
Average = 43.39 , Standard deviation = 1.46
… … … …
- Generation 9
Evaluated 299 individuals
Min = 40.0 , Max = 45.0
Average = 44.12 , Standard deviation = 1.11
- Evolution ends
Best individual:
[0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 1,
1, 0, 0, 0, 1, 0, 0, 0, 1, 1, 0, 0, 0, 1, 0, 0, 0,
1, 0, 0, 1, 1, 1, 0, 0, 1, 0, 1]
Number of ones: 15
符號回歸問題
這是遺傳編程中最著名的問題之一。 所有符號回歸問題都使用任意數據分布,并嘗試用符號公式來擬合最準確的數據。 通常,像 RMSE (均方根誤差)這樣的度量用于度量個體的適應度。 這是一個經典的回歸問題,這里我們使用方程: 5x3-6x2 + 8x = 1
。 我們需要按照上述示例中的所有步驟進行操作,但主要部分是創(chuàng)建基元集,因為它們是個人的構建基塊,因此可以開始評估。 這里將使用經典的基元集。
以下 Python 代碼詳細解釋了這一點 -
import operator
import math
import random
import numpy as np
from deap import algorithms, base, creator, tools, gp
def division_operator(numerator, denominator):
if denominator == 0:
return 1
return numerator / denominator
def eval_func(individual, points):
func = toolbox.compile(expr=individual)
return math.fsum(mse) / len(points),
def create_toolbox():
pset = gp.PrimitiveSet("MAIN", 1)
pset.addPrimitive(operator.add, 2)
pset.addPrimitive(operator.sub, 2)
pset.addPrimitive(operator.mul, 2)
pset.addPrimitive(division_operator, 2)
pset.addPrimitive(operator.neg, 1)
pset.addPrimitive(math.cos, 1)
pset.addPrimitive(math.sin, 1)
pset.addEphemeralConstant("rand101", lambda: random.randint(-1,1))
pset.renameArguments(ARG0 = 'x')
creator.create("FitnessMin", base.Fitness, weights = (-1.0,))
creator.create("Individual",gp.PrimitiveTree,fitness=creator.FitnessMin)
toolbox = base.Toolbox()
toolbox.register("expr", gp.genHalfAndHalf, pset=pset, min_=1, max_=2)
toolbox.expr)
toolbox.register("population",tools.initRepeat,list, toolbox.individual)
toolbox.register("compile", gp.compile, pset = pset)
toolbox.register("evaluate", eval_func, points = [x/10. for x in range(-10,10)])
toolbox.register("select", tools.selTournament, tournsize = 3)
toolbox.register("mate", gp.cxOnePoint)
toolbox.register("expr_mut", gp.genFull, min_=0, max_=2)
toolbox.register("mutate", gp.mutUniform, expr = toolbox.expr_mut, pset = pset)
toolbox.decorate("mate", gp.staticLimit(key = operator.attrgetter("height"), max_value = 17))
toolbox.decorate("mutate", gp.staticLimit(key = operator.attrgetter("height"), max_value = 17))
return toolbox
if __name__ == "__main__":
random.seed(7)
toolbox = create_toolbox()
population = toolbox.population(n = 450)
hall_of_fame = tools.HallOfFame(1)
stats_fit = tools.Statistics(lambda x: x.fitness.values)
stats_size = tools.Statistics(len)
mstats = tools.MultiStatistics(fitness=stats_fit, size = stats_size)
mstats.register("avg", np.mean)
mstats.register("std", np.std)
mstats.register("min", np.min)
mstats.register("max", np.max)
probab_crossover = 0.4
probab_mutate = 0.2
number_gen = 10
population, log = algorithms.eaSimple(population, toolbox,
probab_crossover, probab_mutate, number_gen,
stats = mstats, halloffame = hall_of_fame, verbose = True)
更多建議: