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有很多魔術(shù)師都標演過撲克牌魔術(shù)，外行看著熱鬧，覺得神奇，但若是細究的話，都可以發(fā)現(xiàn)其中的規(guī)律。下面，將通過這個規(guī)律，用 Java 來寫一個簡單的撲克牌魔術(shù)！
前言
用到了Scanner，for循環(huán)，if-else語句，集合，線程的Thread.sleep()方法
話不多說，直接上代碼
代碼
import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;
public class CardMagic {
public static void main(String[] args) {
//1.準備54張牌
//新建一個集合存儲54張牌并打亂順序
ArrayList<String> pokers = new ArrayList<>();
//直接定義兩個數(shù)組并賦值，一個存四種花色，一個存13張牌的值（3，4，5，6，7，8，9，10，J，Q，K，A，2）
String[] kind = {"?","?","?","?"};
String[] number = {"3","4","5","6","7","8","9","10","J","Q","K","A","2"};
//先存大王小王到pokers集合中
pokers.add("大王");
pokers.add("小王");
//組裝兩個集合的數(shù)據(jù)，生成帶花色的52張牌（可以用普通for循環(huán)，也可以用增強for循環(huán)foreach）
for (int i = 0; i < kind.length; i+ +) {
for (int j = 0; j < 13; j++) {
pokers.add(kind[i]+number[j]);
}
}
System.out.println("這里有54張牌："+pokers);//順序打印
//洗牌--打亂pokers集合里的元素順序
Collections.shuffle(pokers);//打亂順序
//再新建一個集合，用來存儲隨機拿出的21張牌(偽隨機：其實是拿出前21張牌，但是pokers集合是隨機打亂順序的，所以每次運行程序，拿出的前21張牌也就不一樣且亂序了)
ArrayList<String> list21 = new ArrayList<>();
for (int i = 0; i < 21; i++) {
list21.add(pokers.get(i));
}
//打印出這21張牌
System.out.println("隨機取出21張撲克牌并打亂順序：");
System.out.println(list21);
System.out.println("請選擇任意一張撲克牌，并記住它?！据斎胄懽帜?#39;y'繼續(xù),輸入其他任意字符結(jié)束游戲！】");
Scanner scanner1 = new Scanner(System.in);
if (scanner1.nextLine().equals("y")){
System.out.println("系統(tǒng)將這21張撲克牌均分為3疊，請等待...");
try {
Thread.sleep(3000);
} catch (InterruptedException e) {
e.printStackTrace();
}
}else {
System.exit(-1);
}
//定義3個集合，每個集合存儲7張牌
ArrayList<String> card1 = new ArrayList<>();
ArrayList<String> card2 = new ArrayList<>();
ArrayList<String> card3 = new ArrayList<>();
for (int i = 0; i < 7; i++) {
card1.add(list21.get(i));
}
for (int i = 7; i < 14; i++) {
card2.add(list21.get(i));
}
for (int i = 14; i < 21; i++) {
card3.add(list21.get(i));
}
System.out.println("第1疊："+card1);
System.out.println("第2疊："+card2);
System.out.println("第3疊："+card3);
//判斷輸入
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
Scanner scanner2 = new Scanner(System.in);
System.out.println("請告訴我你記住的牌在第幾疊~如果在第1疊請輸入數(shù)字1；如果在第2疊請輸入數(shù)字2；如果在第3疊請輸入數(shù)字3");
System.out.println("請輸入:");
//新建3個數(shù)組，分3次重新存重新按指定規(guī)則排序的21張牌
ArrayList<String> list21New1 = new ArrayList<>();
int a = scanner2.nextInt();
if (a==1){
for (int i = 0; i < 7; i++) {
list21New1.add(card2.get(i));
}
for (int i = 0; i < 7; i++) {
list21New1.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New1.add(card3.get(i));
}
}else if (a==2){
for (int i = 0; i < 7; i++) {
list21New1.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New1.add(card2.get(i));
}
for (int i = 0; i < 7; i++) {
list21New1.add(card3.get(i));
}
}else {
for (int i = 0; i < 7; i++) {
list21New1.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New1.add(card3.get(i));
}
for (int i = 0; i < 7; i++) {
list21New1.add(card2.get(i));
}
}
card1.clear();
card2.clear();
card3.clear();
for (int i = 0; i < 21; i++) {
card1.add(list21New1.get(i));
i++;
card2.add(list21New1.get(i));
i++;
card3.add(list21New1.get(i));
}
System.out.println("第1疊："+card1);
System.out.println("第2疊："+card2);
System.out.println("第3疊："+card3);
//判斷輸入
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
Scanner scanner3 = new Scanner(System.in);
System.out.println("請告訴我你記住的牌在第幾疊~如果在第1疊請輸入數(shù)字1；如果在第2疊請輸入數(shù)字2；如果在第3疊請輸入數(shù)字3");
System.out.println("請輸入:");
int b = scanner3.nextInt();
//新建3個數(shù)組，分3次重新存重新按指定規(guī)則排序的21張牌
ArrayList<String> list21New2 = new ArrayList<>();
if (b==1){
for (int i = 0; i < 7; i++) {
list21New2.add(card2.get(i));
}
for (int i = 0; i < 7; i++) {
list21New2.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New2.add(card3.get(i));
}
}else if (b==2){
for (int i = 0; i < 7; i++) {
list21New2.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New2.add(card2.get(i));
}
for (int i = 0; i < 7; i++) {
list21New2.add(card3.get(i));
}
}else {
for (int i = 0; i < 7; i++) {
list21New2.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New2.add(card3.get(i));
}
for (int i = 0; i < 7; i++) {
list21New2.add(card2.get(i));
}
}
card1.clear();
card2.clear();
card3.clear();
for (int i = 0; i < 21; i++) {
card1.add(list21New2.get(i));
i++;
card2.add(list21New2.get(i));
i++;
card3.add(list21New2.get(i));
}
System.out.println("第1疊："+card1);
System.out.println("第2疊："+card2);
System.out.println("第3疊："+card3);
//判斷輸入
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
Scanner scanner4 = new Scanner(System.in);
System.out.println("請告訴我你記住的牌在第幾疊~如果在第1疊請輸入數(shù)字1；如果在第2疊請輸入數(shù)字2；如果在第3疊請輸入數(shù)字3");
System.out.println("請輸入:");
//新建3個數(shù)組，分3次重新存重新按指定規(guī)則排序的21張牌
ArrayList<String> list21New3 = new ArrayList<>();
int c = scanner2.nextInt();
if (c==1){
for (int i = 0; i < 7; i++) {
list21New3.add(card2.get(i));
}
for (int i = 0; i < 7; i++) {
list21New3.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New3.add(card3.get(i));
}
}else if (c==2){
for (int i = 0; i < 7; i++) {
list21New3.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New3.add(card2.get(i));
}
for (int i = 0; i < 7; i++) {
list21New3.add(card3.get(i));
}
}else {
for (int i = 0; i < 7; i++) {
list21New3.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New3.add(card3.get(i));
}
for (int i = 0; i < 7; i++) {
list21New3.add(card2.get(i));
}
}
System.out.println("好了，稍等片刻！讓我猜猜你記住的是什么牌......");
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("真相永遠只有一個,你選的牌是"+list21New3.get(10)+"!");
System.out.println("什么？你說我是運氣好？不！這是“魔法”！");
}
}
運行結(jié)果
其中一次運行結(jié)果：開始我記住的就是梅花K！
魔術(shù)表演步驟
值得一提的是，將21張撲克牌分成3組的具體操作，應(yīng)該是：
將21張撲克牌拿在手上，按順序，從左到右依次發(fā)牌，每發(fā)3次算一輪，一共發(fā)七輪，發(fā)完就會產(chǎn)生3疊牌，每疊7張！
到此這篇關(guān)于用Java來實現(xiàn)一個簡單的撲克牌魔術(shù)的文章就介紹到這了，想要了解更多相關(guān)Java有趣好玩的實戰(zhàn)內(nèi)容嗎，請搜索W3Cschool以前的文章或繼續(xù)瀏覽下面的相關(guān)文章，也希望大家多多支持！
